Formulae - Ambitious

Question 1: Find the value of

d

in the following formula:

d = \frac{x}{y}

, if

x = 5, y = 2

A

d = 2

B

d = \frac{2}{5}

C

d = 5

D

d = \frac{5}{2}

Question 2: Find the value of

Δ

in the following formula:

Δ = b^{2} - 4 a c

, if

b = 5, a = 1, c = 4

A

Δ = 15

B

Δ = 3

C

Δ = 9

D

Δ = 16

Question 3: Transpose the following formula for

h

:

s = \frac{1}{2} a h

A

h = \frac{1}{2} a s

B

h = 2 a s

C

h = 2 \frac{a}{s}

D

h = 2 \frac{s}{a}

Question 4: Transpose the following formula for

x

:

y = \frac{x + 1}{3}

A

y = x + \frac{1}{3}

B

x = y - 3

C

x = \frac{y + 1}{3}

D

x = 3 y - 1

Question 5: Transpose the following formula for

c

:

E = m c^{2}

A

c = \sqrt{\frac{m}{E}}

B

c = \frac{E}{m}

C

c = \sqrt{\frac{E}{m}}

D

c = E m^{2}

Question 6: Transpose the following formula for

q

:

p = \frac{2}{\sqrt{q}}

A

q = \frac{4}{p^{2}}

B

q = \frac{1}{2 p^{2}}

C

q = \frac{1}{2 \sqrt{p}}

D

q = \frac{2}{\sqrt{p}}

Question 7: Transpose the following formula for

x

:

y = \frac{x + 1}{x - 1} + 2

A

x = \frac{y - 3}{y - 1}

B

x = \frac{y - 1}{y - 2} - 2

C

x = \frac{y + 2}{y - 3} - 1

D

x = \frac{y - 1}{y - 3}

Question 8: Transpose the following formula for

b

:

y = a x^{2} + b x + c

A

b = \frac{y - a x^{2} + c}{y}

B

b = \frac{y - a x^{2} - c}{x}

C

b = y - a x^{2} - c

D

b = y + 2 a x^{2} - c

Question 9: Rearrange the formula

u = \sqrt{v - 1} + 1

to make

v

a subject

A

v = \sqrt{u - 1} + 1

B

v = {(u - 1)}^{2} + 1

C

v = u^{2} - 1

D

v = u^{2} - 2

Question 10: Rearrange the formula

2 a x + b y = 3 a y - b x

to make

x

a subject

A

x = 3 a y - b y + 2 a + b

B

x = \frac{y (3 a - b)}{2 a + b}

C

x = \frac{y (2 a + b)}{3 a - b}

D

x = 3 a y - b y - 2 a - b

Test: Formulae - Ambitious

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