Test: Algebra III - Normal

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Question 1:   Solve the equation: $2x+5=15$
$x=5$
$x=2$
$x=10$
$x=-3$
Question 2:   Solve the equation: $13x+169=0$
$x=14$
$x=-12$
$x=-13$
$x=6.5$
Question 3:   Expand the expression: ${\left(x+2\right)}^{2}$
${x}^{2}-2x+4$
${x}^{2}-4x+4$
${x}^{2}+2x+4$
${x}^{2}+4x+4$
Question 4:   Expand the expression: ${\left(x-4\right)}^{2}$
${x}^{2}-4x+8$
${x}^{2}+8x+8$
${x}^{2}-8x+16$
${x}^{2}+4x+8$
Question 5:   Expand the expression: $2\left(x-1\right)\left(x+1\right)$
$2{x}^{2}-2$
$2{x}^{2}$
$2x-2$
$2{x}^{2}-2x+2$
Question 6:   Expand the expression: $\left(a-3\right)\left(a+7\right)$
${a}^{2}+2a-11$
${a}^{2}+4a-21$
${a}^{2}-3a-21$
${a}^{2}-21$
Question 7:   Expand the expression: $-\left(2u-1\right)\left(3+v\right)$
$6u+3uv+v-3$
$6u+3uv-2v+6$
$-6u-2uv+v+3$
$-6v-2uv-v+3$
Question 8:   Expand the expression: $\left(3x+4\right)\left(x-5\right)$
$3{x}^{2}-11x-20$
$3{x}^{2}-19x-20$
$3{x}^{2}-15x-20$
$3{x}^{2}+10x-18$
Question 9:   Rearrange the formula to make $x$ the subject: $y=5x$
$x=-\frac{1}{5}y$
$x=-5y$
$x=\frac{y}{5}$
$x=5y$
Question 10:   Rearrange the formula to make $p$ the subject: $q=\frac{1}{2}p+3$
$p=\frac{1}{2}q-3$
$p=2q-6$
$p=2q-3$
$p=\frac{1}{2}q+3$