Indices - Challenging

Question 1: Solve:

\frac{\sqrt{4^{2} + 3^{2}}}{\sqrt{5^{2}}}

A

1 \frac{3}{5}

B

0

C

1 \frac{2}{5}

D

1

Question 2: Solve:

{(6 \sqrt{3} : 2 \sqrt{3})}^{2}

A

9

B

3

C

18

D

27

Question 3: Solve:

(\sqrt{{(- 5)}^{2}}) \cdot {(- \frac{1}{5})}^{- 1}

A

- 25

B

- 5

C

5

D

25

Question 4: Simplify:

(x^{2} + x^{3}) (x^{4} - x^{5})

A

x^{4} - x^{3}

B

x^{6} - x^{8}

C

2 x^{2} + x

D

x^{4}

Question 5: Simplify:

\sqrt{(\frac{x^{8}}{x^{15}}) \cdot (\frac{x^{2}}{x^{5}})}

A

\frac{1}{x^{5}}

B

\frac{1}{x^{10}}

C

\frac{1}{x^{3}}

D

\frac{1}{x^{2}}

Question 6: Solve:

25^{\frac{1}{2}} + 16^{\frac{1}{2}} + 9^{\frac{1}{2}} - 36^{\frac{1}{2}}

A

9

B

6

C

5

D

2 \sqrt{6}

Question 7: Solve:

{((27^{\frac{2}{3}} \cdot 27^{- \frac{2}{3}}) \cdot (- 1))}^{13}

A

3

B

1

C

0

D

- 1

Question 8: If

2^{x} = 1024

, find

x

A

x = 6

B

x = 10

C

x = 12

D

x = 8

Question 9: If

6^{3 x + 5} = 36^{x + 1}

, find

x

A

x = \frac{1}{3}

B

x = - 6

C

x = - 3

D

x = 6

Question 10: If

2^{2 x - 5} - 128^{x + 1} = 0

, find

x

A

x = - \frac{4}{5}

B

x = - 2 \frac{2}{5}

C

x = 13

D

x = 4

Test: Indices - Challenging

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