Test: Fractions II - Normal

Double click on maths expressions to zoom
Question 1:   Solve: $\frac{2}{5}-\frac{7}{10}$
$-\frac{3}{10}$
$-\frac{2}{5}$
$-\frac{3}{5}$
$-\frac{1}{2}$
Question 2:   Solve: $1\frac{3}{4}+2\frac{1}{2}$
$4\frac{1}{4}$
$3\frac{3}{4}$
$4\frac{1}{2}$
$4$
Question 3:   Solve: $-2\frac{2}{3}+1\frac{5}{6}$
$-1$
$-\frac{2}{3}$
$-\frac{5}{6}$
$-\frac{1}{3}$
Question 4:   Solve: $7\frac{1}{6}+3\frac{1}{12}$
$10\frac{1}{4}$
$10\frac{5}{12}$
$10\frac{5}{6}$
$10$
Question 5:   Solve: $-\frac{1}{3}\cdot 3$
$1$
$0$
$-1$
$\frac{1}{3}$
Question 6:   Solve: $1\frac{1}{3}\cdot \frac{3}{4}$
$1\frac{1}{2}$
$1$
$1\frac{1}{4}$
$\frac{2}{3}$
Question 7:   Solve: $\frac{2}{5}:\frac{4}{5}$
$\frac{1}{4}$
$\frac{8}{25}$
$\frac{3}{4}$
$\frac{1}{2}$
Question 8:   Solve: $\frac{1}{3}:\frac{5}{6}$
$\frac{1}{3}$
$\frac{1}{5}$
$\frac{2}{3}$
$\frac{2}{5}$
Question 9:   Solve: $\sqrt{\frac{4}{9}}-\frac{1}{3}$
$0$
$\frac{2}{3}$
$\frac{1}{3}$
$-1$
Question 10:   Solve: ${\left(\frac{1}{2}\right)}^{2}+\frac{1}{4}$
$1$
$\frac{3}{4}$
$\frac{1}{2}$
$\frac{1}{4}$