Test:
Differentiation II - Challenging
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Question 1:
Find a derivative of the function
y
=
a
r
c
t
g
(
ln
(
x
2
)
)
A
y
'
=
2
x
1
+
(
ln
(
x
2
)
)
B
y
'
=
2
1
+
(
ln
(
x
2
)
)
x
C
y
'
=
1
1
+
(
ln
(
x
2
)
)
D
y
'
=
2
1
+
(
ln
(
x
2
)
)
Question 2:
Find a derivative of a function
y
=
sin
2
(
cos
(
x
)
)
A
y
'
=
sin
(
x
)
sin
(
2
cos
(
x
)
)
B
y
'
=
sin
(
2
cos
(
x
)
)
C
y
'
=
2
sin
(
cos
(
x
)
)
D
y
'
=
−
sin
(
x
)
sin
(
2
cos
(
x
)
)
Question 3:
Find a derivative of a function
y
=
e
cos
(
x
2
)
A
y
'
=
−
2
x
e
cos
(
x
2
)
sin
(
x
2
)
B
y
'
=
e
cos
(
x
2
)
C
y
'
=
−
2
x
e
cos
(
x
2
)
D
y
'
=
−
e
cos
(
x
2
)
sin
(
x
2
)
Question 4:
What is the equation of the tangent to the function
y
=
x
2
+
7
x
−
1
at a point
x
0
=
1
A
y
=
9
x
−
9
B
y
=
9
x
C
y
=
9
x
−
2
D
y
=
9
x
+
2
Question 5:
What is the equation of the tangent to the function
y
=
x
3
+
x
2
+
1
at the point
x
0
=
3
A
y
=
33
x
−
62
B
y
=
33
x
+
37
C
y
=
33
x
−
99
D
y
=
33
x
Question 6:
The Newton's first law of motion is expressed by the formula
s
(
t
)
=
t
3
−
t
2
, where
t
- time (in seconds),
s
(
t
)
- deviation of a point in the moment of time
t
(in meters) from the initial position. Find the speed of movement at the point
t
0
=
1
A
v
=
10
B
v
=
1
C
v
=
5
D
v
=
4
Question 7:
The Newton's first law of motion is expressed by the formula
s
(
t
)
=
t
20
−
t
15
+
t
10
+
20
t
, where
t
- time (in seconds),
s
(
t
)
- deviation of a point in the moment of time
t
(in meters) from the initial position. Find the speed of movement at the point
t
0
=
0
A
v
=
20
B
v
=
19
C
v
=
15
D
v
=
10
Question 8:
Find the amount of the critical points to the graph
f
'
(
x
)
for the segment
[
−
1.5
;
1
)
A
1
B
2
C
3
D
4
Question 9:
Find range when function
f
(
x
)
is ascending, the graph represents
f
'
(
x
)
A
−
∞
;
−
5
∪
1
;
+
∞
B
−
∞
;
−
5
C
−
5
;
1
D
1
;
+
∞
Question 10:
Find range when function
f
(
x
)
is descending, the graph represents
f
'
(
x
)
A
−
∞
;
+
∞
B
−
∞
;
1
C
1
;
+
∞
D
[
−
1
;
1
]
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