# Test: Indices - Ambitious

Double click on maths expressions to zoom
Question 1:   Simplify: ${x}^{3}\cdot {x}^{4}$
${x}^{7}$
${x}^{-1}$
${x}^{12}$
$3{x}^{4}$
Question 2:   Simplify: ${x}^{7}÷{x}^{5}$
${x}^{12}$
${x}^{2}$
${x}^{-2}$
${x}^{7/5}$
Question 3:   Simplify: ${x}^{2}\cdot {x}^{3}\cdot {x}^{4}\cdot {x}^{5}\cdot {x}^{-6}$
${x}^{22}$
${x}^{18}$
${x}^{20}$
${x}^{8}$
Question 4:   Simplify: ${\left(\frac{{x}^{8}}{{x}^{3}}\cdot {x}^{2}\right)}^{2}$
${x}^{49}$
${x}^{9}$
${x}^{14}$
${x}^{25}$
Question 5:   Simplify: ${\left(0.72\right)}^{0}+{2}^{-4}+{9}^{\frac{1}{2}}-{16}^{\frac{1}{4}}$
$2\frac{15}{16}$
$2\frac{13}{16}$
$2\frac{1}{16}$
$2$
Question 6:   Simplify: ${8}^{-1}\cdot 100$
$12.5$
$80$
$125$
$800$
Question 7:   Simplify: ${16}^{\frac{2}{8}}$
$1$
$\sqrt{2}$
$4$
$2$
Question 8:   Simplify: ${4}^{-1}\cdot 100+{4}^{\frac{1}{2}}\cdot 100+{4}^{-\frac{1}{2}}\cdot 100$
$150$
$200$
$175$
$275$
Question 9:   If ${3}^{x}=81$, find $x$.
$x=4$
$x=9$
$x=3$
$x=27$
Question 10:   If ${7}^{x-2}={49}^{2x+5}$
$x=-4$
$x=3$
$x=2$
$x=-1$