# Test: Linear Equations I - Ambitious

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Question 1:   Solve: $5x+13=28$
$x=1$
$x=-3$
$x=2$
$x=3$
Question 2:   Solve: $-3x+7=12$
$x=5$
$x=7$
$x=-\frac{5}{3}$
$x=-\frac{3}{5}$
Question 3:   Solve: $2y+5=3y-9$
$y=14$
$y=-7$
$y=-14$
$y=7$
Question 4:   Solve: $3\left(2y+1\right)-4\left(3y-2\right)=-7$
$y=-3$
$y=-\frac{2}{3}$
$y=\frac{2}{3}$
$y=3$
Question 5:   Solve: $\frac{5}{x}=4$
$x=-\frac{5}{4}$
$x=\frac{4}{5}$
$x=-\frac{4}{5}$
$x=\frac{5}{4}$
Question 6:   Solve: $\frac{2x}{3}-\frac{5\left(x-1\right)}{4}=10$
$x=7$
$x=-15$
$x=13$
$x=-12$
Question 7:   Solve: $\frac{x-5}{3}-\frac{x+2}{5}=1$
$x=21$
$x=23$
$x=19$
$x=17$
Question 8:   Solve: $\frac{1}{x}+\frac{1}{2x}+3=0$
$x=\frac{1}{2}$
$x=\frac{1}{2}$
$x=-\frac{1}{3}$
$x=-\frac{1}{2}$
Question 9:   Solve: $\frac{x}{2}+\frac{x}{3}-\frac{x}{4}=\frac{1}{5}$
$x=\frac{1}{3}$
$x=\frac{12}{35}$
$x=\frac{17}{48}$
$x=2\frac{3}{5}$
Question 10:   Solve: $\frac{1+x}{1-x}=\frac{1}{2}$
$x=-\frac{1}{2}$
$x=-\frac{1}{3}$
$x=\frac{1}{3}$
$x=\frac{1}{2}$