Test: Quadratic Equations I - Ambitious

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Question 1:   Solve: ${x}^{2}=16$
$x=2,x=8$
$x=4,x=0$
$x=-4,x=0$
$x=4,x=-4$
Question 2:   Solve: ${x}^{2}-7x=0$
$\left\{\begin{array}{l}x=1\\ x=-7\end{array}$
$\left\{\begin{array}{l}x=1\\ x=7\end{array}$
$\left\{\begin{array}{l}x=0\\ x=7\end{array}$
$\left\{\begin{array}{l}x=0\\ x=-7\end{array}$
Question 3:   Solve: ${x}^{2}+7x+10=0$
$\left\{\begin{array}{l}x=2\\ x=-5\end{array}$
$\left\{\begin{array}{l}x=-2\\ x=-5\end{array}$
$\left\{\begin{array}{l}x=-2\\ x=5\end{array}$
$\left\{\begin{array}{l}x=2\\ x=5\end{array}$
Question 4:   Solve: $x+9+\frac{20}{x}=0$
$\left\{\begin{array}{l}x=4\\ x=5\end{array}$
$\left\{\begin{array}{l}x=-4\\ x=-5\end{array}$
$\left\{\begin{array}{l}x=-4\\ x=5\end{array}$
$\left\{\begin{array}{l}x=4\\ x=-5\end{array}$
Question 5:   Solve: $3{x}^{2}-16=0$
$\left\{\begin{array}{l}x=\frac{4\sqrt{3}}{3}\\ x=-\frac{4\sqrt{3}}{3}\end{array}$
$\left\{\begin{array}{l}x=\frac{4\sqrt{3}}{3}\\ x=\sqrt{3}\end{array}$
$\left\{\begin{array}{l}x=-\frac{4\sqrt{3}}{3}\\ x=-4\sqrt{3}\end{array}$
$\left\{\begin{array}{l}x=4\sqrt{3}\\ x=-4\sqrt{3}\end{array}$
Question 6:   Solve: ${x}^{2}+5=0$
$x=2.5$
No real roots
$x=-\sqrt{5}$
$x=\sqrt{5}$
Question 7:   Complete the square: $3{x}^{2}-2x+3$
$3{\left(x-2\right)}^{2}+4$
$3{\left(x+\frac{1}{3}\right)}^{2}-\frac{2}{3}$
$3{\left(x-\frac{1}{3}\right)}^{2}+2\frac{2}{3}$
$3{\left(x-1\right)}^{2}+2$
Question 8:   Complete the square: $2{x}^{2}+3x+5$
$2{\left(x+\frac{1}{2}\right)}^{2}-4\frac{1}{8}$
$2{\left(x+\frac{1}{4}\right)}^{2}+3\frac{3}{4}$
${\left(x+\frac{3}{4}\right)}^{2}+4\frac{1}{8}$
$2{\left(x+\frac{3}{4}\right)}^{2}+3\frac{7}{8}$
Question 9:   Solve by completing the square: $2{x}^{2}-4x-1=0$
$\left\{\begin{array}{l}x=\sqrt{\frac{3}{2}}-1\\ x=-\sqrt{\frac{3}{2}}-1\end{array}$
$\left\{\begin{array}{l}x=\frac{\sqrt{3}}{2}\\ x=-\frac{\sqrt{3}}{2}\end{array}$
$\left\{\begin{array}{l}x=2.5\\ x=-0.5\end{array}$
$\left\{\begin{array}{l}x=\sqrt{\frac{3}{2}}+1\\ x=-\sqrt{\frac{3}{2}}+1\end{array}$
Question 10:   Solve by completing the square: $3{x}^{2}-7x-5=0$
$\left\{\begin{array}{l}x=3\\ x=-\frac{5}{6}\end{array}$
$\left\{\begin{array}{l}x=\frac{\sqrt{109}}{6}+\frac{7}{6}\\ x=-\frac{\sqrt{109}}{6}+\frac{7}{6}\end{array}$
$\left\{\begin{array}{l}x=\frac{116}{6}\\ x=-\frac{102}{6}\end{array}$
$\left\{\begin{array}{l}x=\frac{\sqrt{29}}{6}+\frac{2}{3}\\ x=-\frac{\sqrt{29}}{6}+\frac{2}{3}\end{array}$