# Test: Linear Equations - Ambitious

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Question 1:   Solve: $\left(3x+4\right)\left(3x-2\right)+\left(4-3x\right)\left(4+3x\right)=\left(2x-1\right)\left(2x+1\right)-\left(4x-4\right)\left(x+2\right)$
$x=\frac{1}{5}$
$x=\frac{1}{4}$
$x=\frac{1}{10}$
$x=-\frac{1}{10}$
Question 2:   Solve: $\left(x-3\right)\left(x-2\right)-\left(5x-6\right)\left(2x-4\right)=5\left(x-8\right)-{\left(3x-4\right)}^{2}$
$x=2.5$
$x=9$
$x=1.9$
$x=19$
Question 3:   Solve: $\frac{3x+6}{4}-\frac{2x-6}{5}=\frac{x+7}{8}$
$x=-8\frac{1}{9}$
$x=-8$
$x=-7\frac{8}{9}$
$x=-7$
Question 4:   Solve: $\frac{x-4}{3}+\frac{6x+7}{2}=\frac{2x+5}{9}-\frac{3x+5}{6}$
$x=-\frac{33}{67}$
$x=-\frac{44}{65}$
$x=-\frac{25}{67}$
$x=-\frac{57}{65}$
Question 5:   Solve: $\left(3x+2\right)\left(x-5\right)-\left(5x-1\right)\left(2x-3\right)=5-\left(7x+4\right)\left(x-3\right)$
$x=-\frac{8}{9}$
$x=-1\frac{5}{17}$
$x=-2\frac{4}{13}$
$x=-\frac{1}{3}$
Question 6:   Solve: $\frac{2x-5}{8}+\frac{3x-6}{3}=\frac{7x-3}{6}-\frac{2x+1}{4}$
$x=-5\frac{2}{3}$
$x=-6$
$x=-5$
$x=-5\frac{11}{14}$
Question 7:   Solve: $\left\{\begin{array}{l}7x-4y=9\\ 5x-3y=10\end{array}$
$\left\{\begin{array}{l}x=2\\ y=0\end{array}$
$\left\{\begin{array}{l}x=\frac{1}{7}\\ y=-2\end{array}$
$\left\{\begin{array}{l}x=-5\\ y=-3\end{array}$
$\left\{\begin{array}{l}x=-13\\ y=-25\end{array}$
Question 8:   Solve: $\frac{3}{x+4}+\frac{6}{x}=\frac{9}{x-3}$
$x=2$
$x=1$
$x=3$
$x=-1\frac{11}{13}$
Question 9:   Solve: $\left\{\begin{array}{l}2x-y+2z=3\\ x-4y+3z=2\\ 3x+2y-5z=-6\end{array}$
$\left\{\begin{array}{l}x=\frac{2}{7}\\ y=-\frac{3}{5}\\ z=\frac{1}{3}\end{array}$
$\left\{\begin{array}{l}x=1\frac{1}{14}\\ y=1\frac{9}{14}\\ z=2\frac{1}{2}\end{array}$
$\left\{\begin{array}{l}x=-1\frac{1}{14}\\ y=\frac{3}{7}\\ z=2\frac{2}{5}\end{array}$
$\left\{\begin{array}{l}x=\frac{2}{5}\\ y=\frac{1}{6}\\ z=\frac{1}{7}\end{array}$
Question 10:   Solve: $\frac{x-4}{x+4}+\frac{x-6}{x+6}=2$
$x=-2$
$x=-4\frac{4}{5}$
$x=-3$
$x=-3\frac{8}{9}$