Test:
Algebra III - Challenging
×
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Question 1:
If
x
=
−
2
3
, solve:
x
−
1
x
+
1
A
−
5
B
2
9
C
1
1
2
D
−
1
Question 2:
Solve:
a
−
a
−
3
3
=
4
+
3
a
A
a
=
−
9
11
B
a
=
−
2
1
7
C
a
=
9
11
D
a
=
−
1
2
7
Question 3:
Expand:
(
2
x
2
−
1
)
(
3
x
−
2
2
)
A
−
5
x
2
+
2
2
B
6
x
2
2
−
11
x
+
2
2
C
5
x
2
2
−
11
x
+
2
2
−
1
D
6
x
2
2
−
5
x
+
2
Question 4:
Expand:
2
(
a
−
3
)
(
3
3
+
a
)
A
4
a
3
−
18
B
2
a
2
−
3
a
3
−
3
3
C
a
2
−
2
a
3
+
9
D
2
a
2
+
4
a
3
−
18
Question 5:
Expand:
1
3
(
3
x
+
6
)
2
A
3
x
2
+
12
x
+
12
B
6
x
2
+
18
x
+
3
C
9
x
2
+
36
x
+
6
D
2
x
2
+
12
x
+
4
Question 6:
Expand:
(
x
−
5
)
(
x
+
2
)
2
A
2
x
3
−
16
x
−
20
B
16
x
+
20
C
x
3
−
2
x
2
−
24
x
−
20
D
x
3
−
x
2
−
16
x
−
20
Question 7:
Expand:
(
3
a
−
2
)
2
(
a
−
2
)
A
9
a
3
+
6
a
2
+
20
a
−
8
B
9
a
3
+
30
a
2
-
14
a
−
1
C
9
a
3
-
30
a
2
+
28
a
−
8
D
9
a
3
−
6
a
2
+
20
a
−
8
Question 8:
Expand:
4
x
2
(
x
2
−
1
)
−
(
x
2
+
3
)
(
x
2
−
2
)
A
3
x
4
+
5
x
2
−
6
B
5
x
4
−
3
x
2
+
6
C
5
x
4
−
3
x
2
−
6
D
3
x
4
−
5
x
2
+
6
Question 9:
Rearrange the formula to make
y
the subject:
x
y
=
a
−
b
c
A
y
=
x
c
a
−
b
B
y
=
x
(
a
−
b
)
c
C
y
=
a
−
b
x
c
D
y
=
c
x
(
a
−
b
)
Question 10:
Formula for the volume of a cylinder is:
V
=
π
r
2
⋅
h
Rearrange the formula to make
r
the subject
A
r
=
π
h
V
B
r
=
V
π
h
C
r
=
π
⋅
V
h
3
D
r
=
h
⋅
V
π
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